sinx-cosx等于什么
1312次浏览 发布时间:2022-08-24 11:25:59
sinx
sinx-cosx>0
整理不等式得:
√2(sinx/√2-cosx/√2)>0
√2sin(x-π/4)>0
sin(x-π/4)>0
已知正弦函数在(2nπ,π+2nπ)内大于0,即:
2nπ
sinx-cosx>0
整理不等式得:
√2(sinx/√2-cosx/√2)>0
√2sin(x-π/4)>0
sin(x-π/4)>0
已知正弦函数在(2nπ,π+2nπ)内大于0,即:
2nπ